X^2+6x-11=14x-9

Solution for X^2+6x-11=14x-9 equation:

X^2+6X-11=14X-9

We move all terms to the left:

X^2+6X-11-(14X-9)=0

We get rid of parentheses

X^2+6X-14X+9-11=0

We add all the numbers together, and all the variables

X^2-8X-2=0

a = 1; b = -8; c = -2;
Δ = b2-4ac
Δ = -82-4·1·(-2)
Δ = 72
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{72}=\sqrt{36*2}=\sqrt{36}*\sqrt{2}=6\sqrt{2}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-6\sqrt{2}}{2*1}=\frac{8-6\sqrt{2}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+6\sqrt{2}}{2*1}=\frac{8+6\sqrt{2}}{2}
$